Hi all, I am using SOAP of web2py. In local system, Web2py automatic generate xmlns:soap="http://192.168.0.194:8000/bts/service_mb/call/soap"; in body of xml. 192.168.0.194 is the ip address of my server. Then, I deploy the app on internet and I use SoapUI to connect to my service. But, a problem is appeared. Web2py still generate xmlns:soap="http://192.168.0.194:8000/bts/service_mb/call/soap"; in body of xml. So, i cann't connect to my web service. If I edit url manual from 192.168.0.194 to public ip address, I will connect to service normally. I don't want that I must edit URL manual when I need connect to web service. How must I do to expose public ip address in my web service? Thanks!
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