also see here: http://web2py.com/books/default/chapter/29/09/access-control#Central-Authentication-Service
Running a web2py CAS provider is as easy as copying the scaffolding app. In fact any web2py app that exposes the action ## in provider app def user(): return dict(form=auth()) is a CAS 2.0 provider and its services can be accessed at the URL http://.../provider/default/user/cas/login http://.../provider/default/user/cas/validate http://.../provider/default/user/cas/logout (we assume the app to be called "provider"). You can access this service from any other web application (the consumer) by simply delegating authentication to the provider: ## in consumer app auth = Auth(db,cas_provider = 'http://127.0.0.1:8000/provider/default/user/cas') On Tuesday, July 21, 2015 at 10:20:21 AM UTC-7, Derek wrote: > > "Every web2py application is a CAS provider and can optionally be a CAS > consumer." > So any application you have which uses authentication IS a CAS provider. > This is in the book, which you have read. > > http://web2py.com/books/default/chapter/29/09/access-control > > > On Tuesday, July 21, 2015 at 8:41:06 AM UTC-7, Laurent Lc wrote: >> >> Hi, >> >> I have a central server https://cas.monuniversite.fr >> I would like to use it as i do with phpcas for example. >> Could you tell me how to do : >> >> eg: >> >> 1. modify the model db and add .. >> 2. crate a controller and add >> 3. modify apache .. >> >> I am a beginner so ... i ve read the doc but i do not understand >> >> thank you >> > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
