That's the easiest way. If you do want to decode the filename yourself, note the encoded filename is only the last segment of the new filename (i.e., the part after the last "." -- in this case, "73716c2e6c6f67").
Anthony On Tuesday, July 28, 2015 at 4:13:32 PM UTC-4, Limedrop wrote: > > You could try something like this: > > (filename, fullfilename) = > db.tablename.uploadfield.retrieve(record.uploadfield, nameonly=True) > > > > On Wednesday, 29 July 2015 01:05:58 UTC+12, Prasad Muley wrote: >> >> Hi All, >> >> file name gets store as *93f00342868f4085.73716c2e6c6f67.log *in db >> field. >> I've tried to decode it using base64 But didn't get the original file >> name. >> >> Is there any way to decode it and get the original file name? >> >> >> >> -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
