I'd say you need to read the cron chapter of the book. The syntax is |cron_recurrence| |user| |**file_to_execute.py
so, in your case, @reboot root **applications/amlpoc/private/aml_service.py On Wednesday, September 23, 2015 at 3:49:19 PM UTC+2, Blutoh wrote: > > > I have created a task queue that handles a service request because the > operation takes about 4 to 6 minutes to complete, and returns messages and > a file. > The task queue is working well when I start it manually. I am now trying > to create a cron @reboot entry so that the task queue will start when > web2py starts, but I cannot get it to work. The manual start for the queue > is this: > > python web2py.py -S amlpoc -M -R > applications/amlpoc/private/aml_service.py > > > For the cron entry I have tried: > > @reboot root web2py.py -S amlpoc2 -M -R > applications/amlpoc/private/aml_service.py > @reboot root -S amlpoc2 -M -R > applications/amlpoc/private/aml_service.py > @reboot root amlpoc2 -M -R > applications/amlpoc/private/aml_service.py > > but none of these seem to work. Can I call the task queue directly like > this, with parameters? If so, what am I missing? If not, how should I make > the call? > > tnx, > blutoh > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
