Could tou give the good code because it does not run for me and i do not
see what's going wrong
cheers
Le vendredi 20 septembre 2013 20:19:18 UTC+2, 黄祥 a écrit :
>
> hi,
>
> i have an table that contain an upload field for store image, i want to
> show the image in sqlform grid. i tried to using link for achieve that, it
> works well (code 1), but there is no header on it, when i put the header
> (code 2) like describe on the book, it return an error :
> TypeError: 'str' object is not callable.
>
> *code 1 (work, but no header):*
> def product():
> links=[lambda row: A(IMG(_src=URL('download', args=row.image), _width=50,
> _height=50), _href=URL('download', args=row.image))]
> grid=SQLFORM.grid(db.product,
> *links=links)*
> #links=dict(header='image',body=[lambda row: A(IMG(_src=URL('download',
> args=row.image), _width=50, _height=50), _href=URL('download',
> args=row.image))]))
> #links=dict(header='image',body=lambda row: A(IMG(_src=URL('download',
> args=row.image), _width=50, _height=50), _href=URL('download',
> args=row.image))))
> return locals()
>
> *code 2 (not work return an error : TypeError: 'str' object is not
> callable.):*
> def product():
> links=[lambda row: A(IMG(_src=URL('download', args=row.image), _width=50,
> _height=50), _href=URL('download', args=row.image))]
> grid=SQLFORM.grid(db.product,
> #links=links)
> #links=dict(header='image',body=[lambda row: A(IMG(_src=URL('download',
> args=row.image), _width=50, _height=50), _href=URL('download',
> args=row.image))]))
> *links=dict(header='image',body=lambda row: A(IMG(_src=URL('download',
> args=row.image), _width=50, _height=50), _href=URL('download',
> args=row.image))))*
> return locals()
>
> how can i show the image with the header in sqlform.grid?
>
> thanks and best regards,
> stifan
>
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