m1 = db.messages
m2 = db.messages.with_alias('m2')
messages = db(m2.timesent==None).select(m1.ALL, left=m2.on((m1.fromid==m2.
fromid)&(m1.toid==m1.toid)&(m1.timesent<m2.timesent)), orderby=~m1.timesent)will give you the latest messages from each user to another user by descending time. If you want just one user's messages do messages = db((m2.timesent==None)&(m1.fromid==auth.user.id)).select(m1.ALL, left=m2.on((m1.fromid==m2.fromid)&(m1.toid==m1.toid)&(m1.timesent<m2. timesent)), orderby=~m1.timesent) Denes. -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
