Found :
def showonly():
query=(db.personnel.present=='present')
#links=[{'header':T('picture'),'body':lambda row: IMG(_src=row.picture,
_width=50, _height=40, _id='picture')}]
db.personnel.picture.represent = lambda pic,row :
IMG(_src=URL('default', 'download', args=pic))
grid = SQLFORM.grid(query=query, user_signature=False, maxtextlength =
40,deletable=False, \
editable=False, create=False, details=False, \
#links=links, \
fields=[db.personnel.nom,db.personnel.burtelephone,db.personnel.mail,db.personnel.groupe,
db.personnel.picture],orderby=db.personnel.nom)
return dict(grid=grid)
Le lundi 5 octobre 2015 16:27:01 UTC+2, Laurent Lc a écrit :
>
> Hi,
>
> I'd like to show pics for each records when i return a grid. My function
> is :
>
> def showonly():
> query=(db1.test.present=='present')
> grid = SQLFORM.grid(query=query, user_signature=False, maxtextlength =
> 40,deletable=False, \
> editable=False, create=False, details=False, \
> links=[dict(header='picture',body=lambda row:
> A(IMG(_src=URL('download', args=row.picture), _width=50, _height=50),
> _href=URL('download', args=row.picture)))], \
>
> fields=[db1.test.nom,db1.test.burtelephone,db1.test.mail,db1.test.groupe,
> db1.test.picture],orderby=db1.test.nom)
> return dict(grid=grid)
>
> The pic does not appear (header pb i think, but i follow the doc and i do
> not understand)
> And there are 2 times the field "picture" in the columns (it works when i
> click on the link "file")
>
> So i would like to have just one column "picture" whith a pic inside ....
>
> thank you
>
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