Your action (function ajax_form_creator) should return a dict.

What it returns if you type the url direct in your browser address field?

--
Vinicius Assef




On 7 October 2015 at 15:01, Mark Billion <[email protected]> wrote:
> ****** Splits the input "name" attribute up => generates a query => creates
> sqlform => returns form
> def ajax_form_creator():
>     for k,v in request.vars.iteritems():
>         field_array = k.split('-')
>
>         this_page_form = db[field_array[3]].id==field_array[1]
>         db[field_array[3]].client.requires=IS_IN_DB(db(db.client.id == x),
>                                                     "client.id", '%(d_ln)s,
> %(d_fn)s')
>         db[field_array[3]].client.default = x
>
>         ajax_form = SQLFORM(db[field_array[3]], this_page_form,
> deletable=True).process()
>         ajax_form['_id']="Ajax_Form"
>         return ajax_form
>
>
> ******  Button triggers the above script on click.  The result, the
> ajax_form, should be sent to the target div
> <form>
>    <input name="1-2-street_1-client_address" type="button"
> onclick="ajax('{{=URL('default', 'ajax_form_creator')}}',
> [$(this).attr('name')], 'target')" />
> </form>
> <div id="target"></div>
>
> ******
>
> Nothing loads in the target div despite the fact that I know the connection
> works (i.e., I can get it to load other data into the target).  Should I
> serialize the SQLFORM object?  If so, how?  Any thoughts are greatly
> appreciated.
>
> --
> Resources:
> - http://web2py.com
> - http://web2py.com/book (Documentation)
> - http://github.com/web2py/web2py (Source code)
> - https://code.google.com/p/web2py/issues/list (Report Issues)
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-- 
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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