Hi Guys,
I need a hint on how to create back button in web2p y form.
def grid1():
links = [lambda row: A(SPAN(_class='icon
magnifier'),'Form1',_class='button btn
btn-default',_title='Form1',_href=URL("default","form1",args=[row.id]))]
query=(db.test.id>0 )
grid = SQLFORM.grid(query=query,links=links)
return dict(grid=grid)
def form1():
form = SQLFORM.factory(
Field('test',requires=IS_NOT_EMPTY())
)
form.add_button('Back',request.env.http_referer)
return dict(form=form)
It works fine when i click test button in grid view, i'm redirected to
form1 page and when i click Back button I'm again on grid view page.
However when i click Submit without providing any value in Field "test" on
form1, it display error saying field can't be empty - that's where
request.env.http_referer
is probably updated and start to point to form1 instead of grid1. When i
click Back button now, I'm still on the form1 page.
Could You share some hints?
Cheers!
On Friday, 3 January 2014 12:56:47 UTC+1, Gael Princivalle wrote:
>
> Yes, that's the fastest solution. I will tried first to call a different
> html page for the custom single record view page, instead of calling the
> same where I have the grid. Thanks a lot.
>
> Il giorno domenica 29 dicembre 2013 18:28:06 UTC+1, Niphlod ha scritto:
>>
>> your problem is architectural: you just proved that you can't rely on the
>> referrer header to make the app behave like you'd wish.
>> Save the "back" url in a session variable and use that one instead ^_^
>>
>> On Sunday, December 29, 2013 4:02:48 PM UTC+1, Gael Princivalle wrote:
>>>
>>> Goog question.
>>>
>>> In fact initialy referer is my previous page (http:
>>> //.../default/products_listing?keywords=od), and after when the browser
>>> load js and css files referer is my single view page (http:
>>> //.../default/products_listing/view/products/376?keywords=od).
>>>
>>> I think a way to resolve it is making a different html page for the
>>> single row view. Have you got any suggestion ?
>>>
>>> Thanks.
>>>
>>
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