How about?
<a href="{{=URL('custom_download',args = custom_download())}}">download</a>
If you really needs to make it via ajax
<a id="x">download</a>
<script>
jQuery.get('{{=URL('custom_download')}}').done(function(id){jQuery('#x').attr('href','
{{=URL('download')}}'+'/'+id);});
</script>
On Sunday, 6 December 2015 20:28:19 UTC-6, Joseph Faulkner wrote:
>
> I'm developing a simple webapp in web2py and I want to create a link that
> let's the user download a file. Like this:
>
> <a href="{{=URL('download',args = FILE)}}" download>
>
> However, I want to do this without having to pass the FILE to the user in
> the page handler. I want to retrieve an ID from the server asynchronously
> that will correspond to the file I want to download an then pass it to a
> custom download function like this:
>
> <a href="{{=URL('custom_download',args = FILEID)}}" download>
>
> This way, I will be able to upload files to the server asynchronously, (I
> already figured out how to do that) and the download link on the page for
> that file will work right away without having to reload the page.
>
> So, on the server side, I would do something like this:
>
> def custom_download():
> download_row = db(db.computers.FILEID == request.args(0)).select()
> download_file = download_row.filefieldreturn download_file
>
> However, I'm not entirely sure what I need to write in order for this to
> work.
>
--
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- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
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