I had to change to  openpyxl library

Is it any different there?

2016-01-25 11:33 GMT+01:00 Niphlod <[email protected]>:

> watching at the API (http://xlwt.readthedocs.org/en/latest/api.html) it
> seems that the save() method accepts a StringIO object.
> so you just need to create another stream, call save() on it (which will
> fill it with the needed content) and then use it in the zipfile
>
> On Sunday, January 24, 2016 at 5:13:44 PM UTC+1, Yebach wrote:
>>
>> I write to sheet with
>>
>>  xls_dat = xlwt.Workbook(encoding='utf-8')
>>  sheet = xls_dat.add_sheet('sheet 1', cell_overwrite_ok = True)
>>
>>
>> for i,rec in enumerate(workers):
>>             sheet.write(i + 1, 0, rec, style1)
>>             for a, rr in enumerate(dates):
>>                 sheet.write(0, a+1, rr, date_format)
>>                 for b, rrr in enumerate(dict_result):
>>                     if (rrr["rw_worker_nick"] == rec) and rrr["rw_date"]
>> == rr:
>>                         sheet.write(i+1, a+1, rrr["rw_shift"])
>>
>>
>> id I would be creating a file xls_dat.save(fle)
>>
>> but since I want to stream everything i guess i have to do it differently
>>
>> thank you
>>
>> 2016-01-23 20:13 GMT+01:00 Niphlod <[email protected]>:
>>
>>> where is your excel file created ?
>>>
>>> On Saturday, January 23, 2016 at 8:10:18 PM UTC+1, Yebach wrote:
>>>>
>>>> and how do i add excel file to zip?
>>>> On Jan 23, 2016 8:09 PM, "Niphlod" <[email protected]> wrote:
>>>>
>>>>> something is wrong with the code....
>>>>>
>>>>> zipf.writestr('ExportAllWorkers.csv', rows)
>>>>>
>>>>> you can't pipe in to writestr "rows", which in your case is the
>>>>> uber-rich Rows object spitted by DAL, as writestr expects a file-like
>>>>> object or a string.
>>>>>
>>>>> Maybe what you're trying to do is to pipe in the default
>>>>> representation of a Rows, which is a csv-like string.... but you need to
>>>>> force it as str(rows).
>>>>>
>>>>> On Saturday, January 23, 2016 at 7:54:11 PM UTC+1, Yebach wrote:
>>>>>>
>>>>>> Hello
>>>>>>
>>>>>> I have the following problem
>>>>>>
>>>>>> I need to download a csv and an excel file together in a zip file
>>>>>>
>>>>>> I would like to skip the part to create file(s) on server and then
>>>>>> serve it and remove it.
>>>>>>
>>>>>> I am getting an error while using
>>>>>>
>>>>>> import csv, cStringIO
>>>>>>         import zipfile
>>>>>>         exported_chunks_zip = cStringIO.StringIO()
>>>>>>         rows.export_to_csv_file(exported_chunks_zip, delimiter=';',
>>>>>> quoting=csv.QUOTE_NONNUMERIC)
>>>>>>         zipf = zipfile.ZipFile(exported_chunks_zip, "w",
>>>>>> compression=zipfile.ZIP_DEFLATED)
>>>>>>         zipf.writestr('ExportAllWorkers.csv', rows)
>>>>>>
>>>>>> must be string or read-only buffer, not Rows
>>>>>>
>>>>>>
>>>>>> rows is value from db.
>>>>>>
>>>>>> Also when I try to make an excel file how do i serve it to zip?
>>>>>>
>>>>>> Any suggestions?
>>>>>>
>>>>>> Thank you
>>>>>>
>>>>>>
>>>>>>
>>>>>>
>>>>>> --
>>>>> Resources:
>>>>> - http://web2py.com
>>>>> - http://web2py.com/book (Documentation)
>>>>> - http://github.com/web2py/web2py (Source code)
>>>>> - https://code.google.com/p/web2py/issues/list (Report Issues)
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>>>> --
>>> Resources:
>>> - http://web2py.com
>>> - http://web2py.com/book (Documentation)
>>> - http://github.com/web2py/web2py (Source code)
>>> - https://code.google.com/p/web2py/issues/list (Report Issues)
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>>
>>
>>
>> --
>> Lep pozdrav
>>
>> Vid Ogris
>>
>>
>> --
> Resources:
> - http://web2py.com
> - http://web2py.com/book (Documentation)
> - http://github.com/web2py/web2py (Source code)
> - https://code.google.com/p/web2py/issues/list (Report Issues)
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>



-- 
Lep pozdrav

Vid Ogris

-- 
Resources:
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- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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