Yes. Thank you Massimo
On Sunday, February 7, 2016 at 12:38:35 AM UTC-5, Massimo Di Pierro wrote:
>
> It does not get inserted because this:
>
> def index():
> form = SQLFORM(db.song)
> return dict(form = form)
>
> should be
>
> def index():
> form = SQLFORM(db.song).process()
> return dict(form = form)
>
> ;-)
>
> the problem is not in the JS. Also the rating field should be an integer
> else you can run into issues.
>
> On Thursday, 4 February 2016 21:54:14 UTC-6, Ron Chatterjee wrote:
>>
>> Since I am getting an response I am guessing it doesn't work! lol.
>>
>>
>>
>> On Wednesday, January 27, 2016 at 6:42:23 PM UTC-5, Ron Chatterjee wrote:
>>>
>>> *I have the model defined as :*
>>>
>>> db.define_table('song',
>>> Field('title'),
>>> Field('rating'))
>>>
>>> Note*: rating is in the field.
>>>
>>> *controller as:*
>>>
>>> def index():
>>> form = SQLFORM(db.song)
>>> return dict(form = form)
>>>
>>>
>>> *View as you mentioned:*
>>>
>>> {{=form}}
>>>
>>> <script>
>>> jQuery('input.rating,input[name*="rating"]').each(function(){
>>> var span = jQuery('<span style="white-space:nowrap"><span
>>> class="rate0">◎</span><span class="rate1">☆</span><span
>>> class="rate2">☆</span><span class="rate3">☆</span><span
>>> class="rate4">☆</span><span class="rate5">☆</span></span>');
>>> var self = jQuery(this).hide().after(span);
>>> var fill_stars = function() {
>>> var k = parseInt(self.val()) || 0;
>>> for(var i=1; i<6; i++)
>>> span.find('.rate'+i).html((i<=k)?'★':'☆');
>>> };
>>> for(var k=0; k<6; k++) (function(k){
>>> span.find('.rate'+k).mouseover(function(){
>>> for(var i=1; i<6; i++)
>>> span.find('.rate'+i).html((i<=k)?'★':'☆');
>>> }).click(function(){self.val(k);fill_stars();});
>>> })(k);
>>> span.mouseout(fill_stars);
>>> fill_stars();
>>> });
>>>
>>> </script>
>>>
>>>
>>> Results I get is attached but values are not stored in the database. Are
>>> you sure it work at your end like I have it? Just curious.
>>>
>>>
>>>
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