So if I have this field in db.project
Field('project_pdf', 'upload', label='Project PDF', comment='', uploadfolder
='app/uploads'),
I must change to
Field('project_pdf', 'upload', label='Project PDF', comment='', uploadfolder
='app/uploads', default=''),
what content should I put in "default" attribute?
the file name? or folder path?
records have same folder path but different file name.
Even if I change "form.var.project_pdf", the link button won't appear?
Anthony於 2016年2月29日星期一 UTC+8上午8時51分27秒寫道：
>
> The widget gets created when the form is initialized, so if you want to
> specify a value for the file URL, you should do it by setting the "default"
> attribute of the upload field in the db.project table *before* creating
> the table.
>
> Anthony
>
> On Sunday, February 28, 2016 at 10:07:28 AM UTC-5, killzane wrote:
>>
>> I want to modify a record from db.project, and there are a reference
>> field in db.project.
>> So I use SQLFORM.factory to add field to put reference list name.
>>
>> the code I paste is simplify version
>> here is full code
>> project = db((db.project.id == 1) & (db.frature.project_id ==
>> 1)).select(db.project.ALL, db.feature.ALL).first()
>>
>> form = SQLFORM.factory(Field('list_name', 'string', label='List Name'),
>> db.project, db.feature, table_name='project',upload=URL('download'))
>>
>> for t in [db.project, db.project_feature]:
>> query = t.id == project.id if t == db.project else t.project_id ==
>> project.id
>> __copydata(db(query).select(limitby=(0,1)).first(), form.vars,
>> t.fields)
>>
>> so, that me ask another question:
>> How to make SQLFORM.widgets.upload.widget work.
>> I mean make the link button appear.
>> what content I need to put in form.var?
>>
>> Anthony於 2016年2月28日星期日 UTC+8下午9時29分52秒寫道：
>>>
>>> Sorry, still not clear what you are trying to do, and you have not
>>> explained why you are iterating over the Fields of the db.project table.
>>>
>>> On Sunday, February 28, 2016 at 3:48:26 AM UTC-5, killzane wrote:
>>>>
>>>> Because I want to add other field to the form so I use SQLFORM.factory.
>>>>
>>>> And this is my __copydata method
>>>> def __copydata(src, dest, fields):
>>>> if src:
>>>> for k in fields:
>>>> if src.has_key(k):
>>>> dest[k] = src[k]
>>>> return dict()
>>>>
>>>>
>>>>
>>>> Anthony於 2016年2月26日星期五 UTC+8下午9時08分13秒寫道：
>>>>>
>>>>>
>>>>> for t in db.project:
>>>>>> query = (t.id == request.vars.id)
>>>>>> __copydata(db(query).select(limitby=(0,1)).first(), form.vars,
>>>>>> t.fields)
>>>>>>
>>>>>
>>>>> The above is confusing and cannot be the actual code, as it would
>>>>> raise an exception. When you iterate over db.project, you get its Field
>>>>> objects (so each value of "t" is a Field object). Field objects do not
>>>>> have
>>>>> ".id" or ".fields" attributes, so both of the next two lines would result
>>>>> in errors. Perhaps you instead mean to be iterating over Table objects,
>>>>> but
>>>>> it's not clear why you would be doing that, as the form is based on just
>>>>> a
>>>>> single table.
>>>>>
>>>>> Anthony
>>>>>
>>>>
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