Later, I see. So, if I have to call a function within a function I need to
define the other one in the model. Learn something new everyday! Thank a
lot Anthony. You deserve a gold medal.
On Wednesday, March 9, 2016 at 6:44:29 PM UTC-5, Anthony wrote:
>
>
>
> On Wednesday, March 9, 2016 at 6:20:38 PM UTC-5, Ron Chatterjee wrote:
>>
>> I have a pagination that is called by multiple controller, I want to call
>> the pagination function by passing few arguments based on my display
>> requirement and get the output variables rather than keep typing these
>> lines all the time to all the controllers.
>>
>>
>> def pagination():
>> if len(request.args): page=int(request.args[0])
>> else: page=0
>> items_per_page=int(request.args[1])
>> limitby=(page*items_per_page,(page+1)*items_per_page+1)
>> return dict(limitby = limitby,page=page,items_per_page=items_per_page)
>>
>>
>> def item_list():
>>
>> items_per_page= 25;#25 for this page
>> output = LOAD('default','pagination.load', args=[request.args,
>> items_per_page], ajax=True, ajax_trap=True )
>>
>> This don't seem to call the pagination and how to access limitby,
>> items_per_page etc...?
>>
>
> First, it should be:
>
> args=request.args + [items_per_page]
>
> Otherwise, you are creating a list whose first item is another list. Also,
> ajax_trap is irrelevant when ajax=True.
>
> What do you do with "output"? Are you including it in the item_list view?
> What is in the pagination.load view?
>
> Are you sure you want "pagination" to be an Ajax component, or do you just
> want it to be a helper function that returns some pagination parameters
> given some inputs? If the latter, maybe move it to a model, and just use it
> to return the parameters you need:
>
> def item_list():
> ...
> pagination = pagination()
> ...
>
> Anthony
>
>
>
>
>
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