Maybe you can check the table involved and set links option accordingly.
Something like:
table = request.args(0) or ‘dashboard’
links = []
if table == ‘label_dashboard’:
links=[…]
grid = SQLFORM.smartgrid(db.dashboard,linked_tables=[‘label_dashboard’],
links=links)
Not tested
On Wed, Mar 30, 2016 at 6:40 PM, Alessio Varalta <
[email protected]> wrote:
> Hi I have a smartgrid with one child and i want a to add links to my child
> is possibile for example:
>
> I have entity dashboard with a child label_dashboard
>
> So i create the smartgrid
>
> grid = SQLFORM.smartgrid(db.dashboard,linked_tables=['label_dashboard'])
>
> Now I want to add links to label_dashboard is possible? When in the grid i
> go to label_dashboard i want for every row a link button for go to a
> page..I know how use the link button in a grid but for the smartgrid?
>
> --
> Resources:
> - http://web2py.com
> - http://web2py.com/book (Documentation)
> - http://github.com/web2py/web2py (Source code)
> - https://code.google.com/p/web2py/issues/list (Report Issues)
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--
Massimiliano
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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