See
http://web2py.com/books/default/chapter/29/07/forms-and-validators#SQLFORM-in-HTML.
Note, by setting session=None, there is no _formkey in the form and
therefore no CSRF protection. You can remove the session=None, but in that
case you will have to include the _formkey hidden field in the form as
well. The easiest way to do that is to end the form with:
{{=form.custom.end}}
Note, the above includes the _formkey and the _formname hidden fields (so
no need to explicitly include the _formname field) as well as the closing
</form> tag.
You might also want to have a look
at
http://web2py.com/books/default/chapter/29/07/forms-and-validators#Custom-forms.
Anthony
On Wednesday, April 13, 2016 at 6:30:01 AM UTC-4, [email protected]
wrote:
>
> Newby question.
>
> def mydef():
>
> form = SQLFORM(db.mytable)
> if form.process.accept():
> conditions here
> return locals()
>
> view:
> {{=form}}
>
> What if form is defined in the view first.
>
> How to invoke the controller. if in view
>
> <form>
> first name: <br>
> <input type="text" name="firstname"><br>
> last name: <br>
> <input type="text" name = "lastname">
> </form>
>
> How to process this form and accept it in the controller. like if
> form.process.accept():....
>
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