Frankly it's not clear what you want to achieve. That being said you have a timeout on the task itself and an api to stop a running task. Not sure what you need in addition to those...
On Thursday, May 26, 2016 at 4:28:40 AM UTC+2, Andrew Evans wrote: > > Hello, I am running a scheduler that I would like to timeout the > scheduler_run on a failed execution of my function so that it will attempt > to retry running it. > > > try: > attempt to run my code > except: > failed to run, timeout scheduler_run to reattempt > > > Also I have parameters that when a value has been met I would like to > remove the users scheduled task. > > > if views >= amount: > update the db > remove scheduler_task > > > I am not sure how to do this or if timing out the scheduler is the best > practice and would appreciate any help. > > > *cheers > > Andrew > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
