Try INNER JOINS.
On Monday, June 13, 2016 at 6:31:33 PM UTC+3, Gael Princivalle wrote:
>
> New model:
> db.define_table('categories):
> Field('title', type='string'))
>
> db.define_table('products'):
> Field('code', type='string'),
> Field('category', reference 'categories'))
>
> With groupby I obtain a good result.
>
> results = db(db.products).select(db.products.category, groupby=db.products
> .category)
>
> But I need to order the results by the category title.
>
> If I do like that:
> results = db(db.products).select(db.products.category, orderby=db.product.
> category.title, groupby=db.products.category)
>
> Ticket is : 'Field' object has no attribute 'title'
>
> Is there a way to order these results, or make a query that selct only the
> categories in db.categories that are in db.products ?
>
> Il giorno giovedì 9 giugno 2016 12:56:57 UTC+2, [email protected]
> ha scritto:
>>
>> Looks like you want a subquery. You'll need to decide which of the items
>> to choose when you have a given category_code.
>> Say you want the first item with a given category code:
>>
>> sub_query = db()._select(db.products.id.min(), groupby=db.products.
>> category_code)
>> results = db(db.products.id.belongs(sub_query)).select()
>>
>>
>> On Wednesday, 8 June 2016 15:10:33 UTC+1, Gael Princivalle wrote:
>>
>>> Hello.
>>>
>>> Is there a way to select some rows without duplicates for a specific
>>> field ?
>>>
>>> MODEL:
>>> db.define_table('products'):
>>> Field('code', type='string'),
>>> Field('category_code', type='integer'))
>>>
>>> ROWS:
>>> code / category_code
>>> A1125 / 3
>>> C2214 / 2
>>> D235 / 3
>>> Z886 / 1
>>>
>>> I would like to make a select that give this result:
>>> code / category_code
>>> A1125 / 3
>>> C2214 / 2
>>> Z886 / 1
>>>
>>> Someone have an idea ?
>>>
>>> Thanks.
>>>
>>>
>>>
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