But you can't execute this line:
return dict(club=club[0],address=address[0],nfas=nfas)
If either the club or the address is empty.
Maybe you need something like:
address=address or address[0]
...which will do a lazy evaluation of address[0] only if address
exists.
But then you have to test for None later when you use it in the view.
On Jun 30, 11:08 am, annet <[email protected]> wrote:
> I am not sure. I want to display the club, address or nfa details if
> one or more of them contain(s) values.
>
> if not (p or q or r): does exactly that.
> not (0 or 0 or 0) evaluates to true in all other cases it evaluates to
> false.
>
> The other option would be to only display the details if club, address
> and nfa all contain values
>
> if (p and q and r) would accomplish that (1 and 1 and 1) evaluates to
> true.
>
> But that doesn't make any difference to the ticket being issued.
>
> Kind regards,
>
> Annet.
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"web2py Web Framework" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/web2py?hl=en
-~----------~----~----~----~------~----~------~--~---
