can i change auth.has_membership(role) to another user? i need to iterate over all users and find if they belong to some group.
I have a list [4,5,1] with the id of the group i need to check. Regards António 2016-11-12 0:08 GMT+00:00 Anthony <[email protected]>: > On Friday, November 11, 2016 at 4:15:50 PM UTC-5, 黄祥 wrote: >> >> i assume the same thing goes to auth.user vs auth.is_logged_in(), >> auth.user faster than auth.is_logged_in() because auth.user didn't hit the >> database, isnt it? >> > > No, login status is maintained in the session -- auth.is_logged_in() does > not hit the database. Note, you can always look at the source code to see > how something works -- here's the body of that function: > > if self.user: > return True > return False > > As you can see, it's exactly equivalent to simply checking auth.user. > > Anthony > > -- > Resources: > - http://web2py.com > - http://web2py.com/book (Documentation) > - http://github.com/web2py/web2py (Source code) > - https://code.google.com/p/web2py/issues/list (Report Issues) > --- > You received this message because you are subscribed to the Google Groups > "web2py-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > For more options, visit https://groups.google.com/d/optout. > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
