I'm not sure it's considered part of the public API (it's not in the book), 
but you can do:

filepath = db.mytable.myupload.retrieve_file_properties(row.myupload)['path'
]

The returned dictionary also includes a "filename" key, which holds the 
decoded (i.e., original) filename.

More generally, when uploadseparate=True, the filepath is 
/path/to/uploadfolder/tablename/fieldname/uuid[:2], where uuid is the 
16-character UUID segment in the stored filename (i.e., 
tablename.fieldname.uuid.base64encoded_filename).

Anthony

On Tuesday, December 27, 2016 at 9:51:45 AM UTC-5, Manuele wrote:
>
> Hi! 
>
> Other than the methods "store" and "retrieve" of a field is there a 
> programmatic way to get from a row just the path where a file is stored 
> on the filesystem (expecially when uploadseparate option is set to True)? 
>
>
> Thank you very much 
>
>     Manuele 
>
>

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