Can Someone write a slice on how to connect an android app to a web2py server, using java and py
On Wednesday, December 9, 2015 at 12:47:19 PM UTC+2, noam cohen wrote: > > > <https://lh3.googleusercontent.com/--0rOdzb1tm0/VmgGeoHk3QI/AAAAAAAAF2w/hJkq2dR1k_c/s1600/login_screen.png> > > Hi > I need help implementing this scenario: > > user opens the android app. > app checks if he is currently logged in. > if not, open the login web page ( in a webview - as seen in the screenshot) > from here, new users can register. > user enter credentials. > login result (pass/fail) is used by the app logic to decide how to > continue. > The user SHOULD not have to see web pages outside the application (i.e. > opening the browser) > Once the user is logged in, he updates the web2py server with the > equivalent of c -> s : foo(user_id, data1,data2) > > > 1. how can I check if user is currently logged in? I saw the session > cookie but not sure how to infer from it the status. Also, a user could > have logged in long time ago, have the cookie but the session will expire. > I guess something like this is needed in controllers/hello.py: ( i.e. > start > by sending GET http://mysite/my_app/hello/logged > @auth.requires_login() > def logged(): return dict(message="hello logged user") > 2. I guess I don't really need the user_id field in the client side. > What is the proper way to get actions associated with this user? in other > words, each user has database updates relevant only for him. > > > > This is similar to > https://groups.google.com/forum/?fromgroups#!searchin/web2py/login/web2py/22hXvhMF-ws/gEb62ZJMabEJ > but > not exactly. > > Once I have it working, I will upload the java class to the web2py splices. > > thanks! > Noam > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
