On Saturday, January 27, 2018 at 6:44:22 AM UTC-5, Alfonso Serra wrote: > > what do i need to return at an error handler controller to get the same as > web2py does by default? Let me ellaborate: > > I have implemented "routes on error" at routes.py like: > > routes_onerror = [ > (r"*/*", r"/error") > ] > > so any error goes through "/myapp/controllers/error.py" (note i have > removed the appname from any route, thats not the issue). > > on errors.py i have some code for development only: (skip the tickets > system) > def index(): > > import mechanize > url = "http://127.0.0.1/admin/default/ticket/"; + request.vars.ticket > br = mechanize.Browser() > br.set_handle_robots(False) > resp = br.open(url) > br.form = list(br.forms())[0] > > br.form['password'] = "1234" > req = br.submit() > return req.read() > > If i write this on a random controller: > raise HTTP(400, "cant do it") > > i would like that response to get to the browser instead the one at > errors.py so: > > what do i need to return at errors.py so i get this 400 error with the > message? >
See https://groups.google.com/d/msg/web2py/Mg5kK2AuoMQ/VQM7Rr8jBAAJ for some ideas. The general idea is to set some flag when you raise your own errors (e.g., using special error codes, adding a key/value to the WSGI environment, etc.), and then look for that flag in your error handler in order to take the appropriate action there. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
