Are you using the default layout.html in the welcome app? If so, it no
longer uses the MENU() helper, so the solutions you reference do not work.
Instead, you will have to edit the code in layout.html to do what you want.
Anthony
On Monday, August 20, 2018 at 4:46:22 AM UTC-4, lyn2py wrote:
>
> Hello,
>
> I am using the latest pulled version from GitHub and I am not able to use
> either of the solution listed by Anthony
>
> Version 2.17.1-stable+timestamp.2018.08.05.17.57.00
>
> Solution 1:
> ('Label', False, dict(_href=URL(...), _target='blank'))
>
> gave this link: http://
> 127.0.0.1:8000/app/ctrl/index/%7B'_href':%20'/app/ctrl/func
> ',%20'_target':%20'blank'%7D
>
>
> and
>
> Solution 2:
> ('', False, A('Label', _href=URL(...), _target='blank'))
>
> gave this link: http://127.0.0.1:8000/app/ctrl/index/%3Ca%20href=
>
> But if I used the A(...) code in a controller, it prints to console and
> screen with correct HTML.
>
> Has there been a change in code? Please assist... Thanks!
>
>
>
>
> On Monday, April 15, 2013 at 9:50:29 AM UTC+8, Anthony wrote:
>>
>> A menu item can be specified like this:
>>
>> ('Label', False, dict(_href=URL(...), _target='blank'))
>>
>> or this:
>>
>> ('', False, A('Label', _href=URL(...), _target='blank'))
>>
>> Note, in the second case, the third element can be any HTML helper object
>> (including nested helpers).
>>
>> Anthony
>>
>> On Sunday, April 14, 2013 6:09:56 PM UTC-4, BlueShadow wrote:
>>>
>>> Hi,
>>> I like to be able to set some link attributes in my response menu:
>>> I want some links to open in a new tab: target="blank"
>>> and I would love to set some alt atributes for the links in the response
>>> menu.
>>> Is that even possible?
>>> thanks
>>>
>>
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