Hi Anthony, thank you for your time.
I tried the method you suggested, but here is my problem: after calling the
method, the row object isn't updated.
row = db.person(1)
row.change_name('Lisandro')
print(row.name)
This doesn't print "Lisandro".
Instead, it prints the name the person had before the call.
If I want to print the new name, I have to retrieve the row again like this:
row = db.person(1)
row.change_name('Lisandro')
row = db.person(1)
print(row.name)
I was wondering if it was possible to avoid having to retrieve the record
again.
El viernes, 26 de abril de 2019, 17:16:10 (UTC-3), Anthony escribió:
>
> def change_name(row, name):
> db(db.person.id == row.person.id).update(name=name)
>
> db.define_table('person',
> Field('name'),
> Field.Method('change_name', change_name))
>
> row = db.person(1)
> row.change_name('Lisandro')
>
> Anthony
>
> On Friday, April 26, 2019 at 12:21:28 PM UTC-4, Lisandro wrote:
>>
>> I've been working with Virtual Fields for a while, but now I'm wondering,
>> how could I write a Virtual Field method that modifies the row itself?
>>
>> I mean, I would like to do something similar that what the
>> .update_record() method does. When you call row.update_record(), the row
>> object is updated with the new values.
>>
>> I've tried returning the row object in the method definition function but
>> it doesn't work.
>>
>> I'm wondering, is it even possible to implement something like that? Any
>> comment or suggestion will be much appreciated.
>>
>> Thanks!
>> Warm regards,
>> Lisandro.
>>
>
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