On Tuesday, June 4, 2019 at 3:16:12 PM UTC-7, Ben Duncan wrote: > > I've been trying to run it ... When you click on the button it does nothing > > *Ben Duncan* > DBA / Chief Software Architect > Mississippi State Supreme Court > Electronic Filing Division > > >
When I replace the "ajax-info.txt" with a real URL (that is, one for a web2py function on my server, and which returns a txt file), I see the network access, including a response with HTTP status 303. For some reason (cookie management?) it doesn't work for me to login via a separate tab, and each time I click the button I get a different cookie. I've been poking at sending credentials, but I still get the 303 response and I apparently am not setting the Authorization header as I think I am, but only setting Access-Control-Request-Headers to "authorization". And there is also "allow origin" issues, because file://tmp/test.html comes from a different address than the server. HTH /dps On Tue, Jun 4, 2019 at 4:35 PM Anthony <abas...@gmail.com <javascript:>> > wrote: > >> What are you trying to do? That code should work fine in web2py, as it's >> just Javascript. You just need to have it call a web2py URL. Of course, >> web2py includes some built-in mechanisms for handling Ajax requests, such >> as the ajax() Javascript function and the LOAD() helper to create Ajax >> components. >> >> Anthony >> >> On Tuesday, June 4, 2019 at 3:23:11 PM UTC-4, Ben Duncan wrote: >>> >>> Ok, the following is code from w3 schools: >>> https://www.w3schools.com/js/js_ajax_intro.asp >>> >>> The code is as follows : >>> >>> <!DOCTYPE html> >>> <html> >>> <body> >>> >>> <div id="demo"> >>> <h2>The XMLHttpRequest Object</h2> >>> <button type="button" onclick="loadDoc()">Change Content</button> >>> </div> >>> >>> <script> >>> function loadDoc() { >>> var xhttp = new XMLHttpRequest(); >>> xhttp.onreadystatechange = function() { >>> if (this.readyState == 4 && this.status == 200) { >>> document.getElementById("demo").innerHTML = >>> this.responseText; >>> } >>> }; >>> xhttp.open("GET", "ajax_info.txt", true); >>> xhttp.send(); >>> } >>> </script> >>> >>> </body> >>> </html> >>> >>> The question is how do I get this code to run under web2py ? >>> >>> Thanks ... >>> >>> *Ben Duncan* >>> DBA / Chief Software Architect >>> Mississippi State Supreme Court >>> Electronic Filing Division >>> >> -- >> Resources: >> - http://web2py.com >> - http://web2py.com/book (Documentation) >> - http://github.com/web2py/web2py (Source code) >> - https://code.google.com/p/web2py/issues/list (Report Issues) >> --- >> You received this message because you are subscribed to the Google Groups >> "web2py-users" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to web...@googlegroups.com <javascript:>. >> To view this discussion on the web visit >> https://groups.google.com/d/msgid/web2py/9b9fa219-3038-4d61-9206-a5ab134f783e%40googlegroups.com >> >> <https://groups.google.com/d/msgid/web2py/9b9fa219-3038-4d61-9206-a5ab134f783e%40googlegroups.com?utm_medium=email&utm_source=footer> >> . >> For more options, visit https://groups.google.com/d/optout. >> > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/web2py/e58217b0-df00-4897-aa57-40a92b019ada%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
