On Mon, Sep 14, 2009 at 1:54 PM, mdipierro <[email protected]> wrote:
>
> import urllib
>
> html=urllib.urlopen(URL(.....)).read()
>
> On Sep 14, 2:47 pm, "V. K" <[email protected]> wrote:
>> Hi,
>>
>> I want to call a web2py web service from the shell and obtain the HTML
>> response (not using a web browser).
>> From example:
>>
>> For the service:http://www....../a/c/f/x/y?z=t
>>
>> Construct the URL object:
>>
>> URL('a','c','f',args=['x','y'],vars = dict(z='t'))
>>
>> and then how do I call the controller using this object to obtain the
>> response HTML?



I just happened to stumble on this at the bottom of:

http://web2py.com/examples/default/tools

---------------------------------------------------

Fetch a URL

The Python module urllib does not work well on the Google App Engine.
For this reason we created a portable function for fetching url that
works everywhere, including GAE:

from gluon.tools import fetch
html = fetch("http://www.web2py.com";)

----------------------------------------------------

-wes

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