How does it work for a service? This is how I call the method: http://127.0.0.1:8000/videotag/default/call/xml/function/arg
This doesn't render using generic.xml (I tried modifying it). Any ideas? On Oct 15, 12:51 pm, Thadeus Burgess <[email protected]> wrote: > Doesn't the view get rendered to a generic.xml? You should be able to use a > custom view for the controller to render the xml exactly how you want it. > > -Thadeus > > On Thu, Oct 15, 2009 at 1:55 AM, Adi <[email protected]> wrote: > > > Hi, > > > I have an HTTPService which returns a result of a query as xml, which > > I need to display in Flex 3 frontend. > > > Here's the simplified code snippet: > > > @service.xml > > def records(): > > rows = db().select(db.videodata.id, db.videodata.title, > > db.videodata.thumbnail, \ > > db.videodata.flvcopy, > > db.videodata.description) > > return rows > > > When I call this service, the results look like this: > > > <item><id>1</id><title>Test Video</title><flvcopy></ > > flvcopy><thumbnail>videodata.thumbnail. > > 9c41e14b670ddbd2.61616a74616b315f312e6a7067.jpg</ > > thumbnail><description>This is the description of a test video</ > > description></item><item><id>2</id><title>Another File</ > > title><flvcopy></flvcopy><thumbnail>videodata.thumbnail. > > 9ef97a75a1aed552.6261636b626c75652e676966.gif</ > > thumbnail><description>This is a second record for testing</ > > description></item> > > > Basically there is no "root" element, just query results in every > > <item></item> tag. This is resulting in parsing error. How can I > > return the results of the query in a well-formed xml? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---
