hi massimo,

i didn't undertand the pagination logic here. could you please
explain?

sincerely
Mengu

On Nov 4, 5:30 pm, mdipierro <[email protected]> wrote:
> limitby=(a,b)
>
> returns rows[i] for a <= i < b
>
> On Nov 4, 3:30 am, Mengu <[email protected]> wrote:
>
> > hi everyone.
>
> > i have a problem with paginating my results. i guess i didn't
> > understand the logic in limitby.
>
> > normally an sql query SELECT * FROM post LIMIT 2 OFFSET 0 displays the
> > first 2 results. And I can get the first 2 records with db
> > (db.post.id>0).select(limitby(0,2)). so limit is 2 and offset is 0.
>
> > however the problem is, this query fails:
> > db(db.post.id>0).select(limitby(2,2)). in this query the limit is 2
> > and the ofset is 2 either. however it doesn't return select * from
> > post limit 2 offset 2 but it returns select * from post limit 0 offset
> > 2 because in sql.py 2846 limit is lmax - lmin and offset is lmin. i
> > have edited that line as sql_o += ' LIMIT %i OFFSET %i' % (lmax, lmin)
> > and it is working as expected. now my pagination is working.
>
> > here is my codes for pagination:
> > perpage = 2
> > totalposts = db(db.post.id > 0).count()
> > totalpages = totalposts / perpage
> > page = int(request.vars.page) if request.vars.page else 1
> > limit = int(page - 1) * perpage
> > posts = db(db.post.id > 0).select(orderby=~db.post.id, limitby=(limit,
> > perpage))
>
> > please let me know if there's another page for doing this.
>
> > sincerely
> > Mengu
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