the one in gluon tools does prettydate(request.now,T)
On Feb 18, 7:49 am, Iceberg <[email protected]> wrote: > IMHO, the example's code is good, but not cool enough to be put in the > book. Every programmer saw those ordinary if...elif...elif...else > cliche in their first program language book before. People can > probably write their own if...elif...else in less time, than STFW or > RTFM to find our prettydate(). > > So, we need some extra flavor to compensate the time a guy spent to > find our prettydate(). How about making it i18n-friendly? Something > like this. > > class PrettyDate(object): > def __init__(self,T): > self.T=T # > def __call__(self, d): > dt = datetime.now() - d > if dt.days >= 2*365: > return self.T('%d years ago') % int(dt.days / 365) > elif ...: > ...... > > Then, in the model we can initialize an instance by: > prettydate = PrettyDate(T) > In controller we can do: > prettydate(d) > Of course developers need to localize their own language strings in > their own environment. > > Just my $0.02 > > On Feb16, 1:21pm, Jason Brower <[email protected]> wrote: > > > These examples would be a very good edition to the book > > -- > > J > > > On Mon, 2010-02-15 at 16:19 -0800, mdipierro wrote: > > > for lack of a better option I put it in tools for now. > > > > On Feb 15, 5:56 pm, Richard <[email protected]> wrote: > > > > added a few more cases: > > > > > def prettydate(d): > > > > try: > > > > dt = datetime.now() - d > > > > except: > > > > return '' > > > > if dt.days >= 2*365: > > > > return '%d years ago' % int(dt.days / 365) > > > > elif dt.days >= 365: > > > > return '1 year ago' > > > > elif dt.days >= 60: > > > > return '%d months ago' % int(dt.days / 30) > > > > elif dt.days > 21: > > > > return '1 month ago' > > > > elif dt.days >= 14: > > > > return '%d weeks ago' % int(dt.days / 7) > > > > elif dt.days >= 7: > > > > return '1 week ago' > > > > elif dt.days > 1: > > > > return '%d days ago' % dt.days > > > > elif dt.days == 1: > > > > return '1 day ago' > > > > elif dt.seconds >= 2*60*60: > > > > return '%d hours ago' % int(dt.seconds / 3600) > > > > elif dt.seconds >= 60*60: > > > > return '1 hour ago' > > > > elif dt.seconds >= 2*60: > > > > return '%d minutes ago' % int(dt.seconds / 60) > > > > elif dt.seconds >= 60: > > > > return '1 minute ago' > > > > elif dt.seconds > 1: > > > > return '%d seconds ago' % dt.seconds > > > > elif dt.seconds == 1: > > > > return '1 second ago' > > > > else: > > > > return 'now' > > > > > > On Feb 14, 3:13 pm, selecta <[email protected]> wrote: > > > > > > > This is not 100% web2py related but I am sure if this will be > > > > > > answered > > > > > > many of you will profit at some point from it. > > > > > > > Is there a python module that helps you to display dates and times > > > > > > nice e.g. > > > > > > > just now (for within the last 5 minutes) > > > > > > 2 hours ago > > > > > > 2 days ago > > > > > > 15th February 2009 > > > > > > ... > > > > > > > I guess somebody must have done that already, right? -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.
