Sorry for the misunderstanding. When I said it was horrible I meant that redirecting stdout is not a very elegant solution, but works. Don't know how you could do what you need, showing the progress of the script.
Regards, Tiago -- On Wed, Feb 24, 2010 at 10:35 PM, AsmanCom <[email protected]> wrote: > Yo Tiango, > many thanks for your effort. > > But if you say: > > this is horrible! > > I´ll forget about that. > > > The least you should do is transform your scripts > > so that instead of printing, they return the strings > that's what i meant with: "(may i could change "print" to "return")" > > But i don´t know how to do this? > > May we could return to my example: > > def chunk_report(bytes_so_far, chunk_size, total_size): > percent = float(bytes_so_far) / total_size > percent = round(percent*100) > return percent > > > which is called by the def chunk_read: > while 1: > chunk = response.read(chunk_size) > bytes_so_far += len(chunk) > > if not chunk: > break > > if report_hook: > report_hook(bytes_so_far, chunk_size, total_size) > > How to display the output of chunk_report properly? (or how to update > the ProgressBar with that output?) > > Best regards, > > Dieter Asman > > - AsmanCom - > Germany > > On 24 Feb., 23:09, Tiago Almeida <[email protected]> wrote: > > This is nasty as hell but you can redirect stdout to a string. Execute > your > > untouched scripts, all they print goes to the string and then, in the > web2py > > controller return that string instead of a dict. > > > > Example: > > -- file print1_script.py: -- > > def print1(): > > print "1" > > > > #call print1 > > print1() > > > > -- file whatever.py: -- > > import sys > > from cStringIO import StringIO > > > > #redirect stdout to string > > sys.stdout = mystdout = StringIO() > > > > #execute script print1_script.py > > execfile('print1_script.py') > > > > #reset the stdout > > sys.stdout = sys.__stdout__ > > > > #the output is available *as a string* in mystdout.getvalue() > > print mystdout.getvalue() > > > > --- end -- > > > > Again, this is horrible! The least you should do is transform your > scripts > > so that instead of printing, they return the strings. Then in web2py > > controller you just return whatever your function returns. > > > > Regards, > > Tiago > > ---- > > > > On Wed, Feb 24, 2010 at 5:33 PM, AsmanCom <[email protected]> wrote: > > > Hi Tiango, > > > > > no i need an equivalent for print, like: > > > > > def print_1(): > > > print "1" > > > print "2" > > > = > > > 1 > > > 2 > > > > > def print_2(): > > > while True: > > > print "1" > > > = > > > 1 > > > 1 > > > 1 > > > 1 > > > ... > > > > > I need to execute scripts like in terminal, but output rendered in > > > html. (should be very simple?) > > > > > Best regards, > > > > > Dieter Asman > > > > > - AsmanCom - > > > Germany > > > > > On 24 Feb., 18:17, Tiago Almeida <[email protected]> wrote: > > > > > for quick development-shots, i need to execute my untouched(may i > > > > > could change "print" to "return") Python scripts(..with loops) in > the > > > > > Controller. > > > > > The output should be renderd direct via http, without long-winded > > > > > setting up the view for each function. > > > > > Is that possible? > > > > > > If I understand you want to return a string directly without being > > > processed > > > > by the view. > > > > On a controller function, if you return a string (not a dict) it will > be > > > > rendered as is. > > > > > > Tiago > > > > -- > > > > > > On Wed, Feb 24, 2010 at 4:48 PM, AsmanCom <[email protected]> wrote: > > > > > Hi, > > > > > > > for quick development-shots, i need to execute my untouched(may i > > > > > could change "print" to "return") Python scripts(..with loops) in > the > > > > > Controller. > > > > > The output should be renderd direct via http, without long-winded > > > > > setting up the view for each function. > > > > > Is that possible? > > > > > > > To my next concern.... > > > > > > > On my actual Project i have simple form field with submit button on > my > > > > > controller: > > > > > form = SQLFORM.factory(Field('update_url', default='http://. > > > domain.org/ > > > > > text_file.txt <http://domain.org/%0Atext_file.txt>', > > > > > requires=IS_NOT_EMPTY())) > > > > > > > On Submit the text file should be downloaded to Server indicated by > an > > > > > Progress Bar on the Page. > > > > > Next the file should be inserted to the DB line by line(for loop > with > > > > > regex) and again indicated by the same Progress Bar ..... > > > > > > > My Code so far(... relies on clienttools example specifically on > > > > > jqueryUI-progressbar and an urllib2 +report_hook snippet i´ve found > > > > > somewhere): > > > > > > _______________________________________________________________________ > > > > > def chunk_report(bytes_so_far, chunk_size, total_size): > > > > > percent = float(bytes_so_far) / total_size > > > > > percent = round(percent*100) > > > > > return percent > > > > > > > if bytes_so_far >= total_size: > > > > > return ('100.0') > > > > > > > def chunk_read(response, chunk_size=8192, report_hook=None): > > > > > total_size = response.info > ().getheader('Content-Length').strip() > > > > > total_size = int(total_size) > > > > > bytes_so_far = 0 > > > > > > > while 1: > > > > > chunk = response.read(chunk_size) > > > > > bytes_so_far += len(chunk) > > > > > > > if not chunk: > > > > > break > > > > > > > if report_hook: > > > > > report_hook(bytes_so_far, chunk_size, total_size) > > > > > > > percent = float(bytes_so_far) / total_size > > > > > percent = round(percent*100) > > > > > return percent #bytes_so_far > > > > > > > def url_progress(): > > > > > wrapper = DIV(progress,_style="width:400px;") > > > > > jqueryui_progress() > > > > > form = SQLFORM.factory(Field('update_url', > > > > > default='http://.domain.org/text_file.txt', > requires=IS_NOT_EMPTY())) > > > > > if form.accepts(request.vars, session): > > > > > response.flash = "Got it!" > > > > > try: > > > > > import urllib2 > > > > > openurl = urllib2.urlopen(request.vars.update_url) > > > > > chunk_read(openurl, report_hook=chunk_report) > > > > > except Exception, e: > > > > > session.flash = DIV(T('Unable to download from url > > > > > because:'),PRE(str(e))) > > > > > redirect(URL(r=request)) > > > > > event.listen('submit',"form","return confirm('Are you sure?');") > # > > > > > adds a confirmation to submit > > > > > page.ready(jq("update_oui").focus()()) > > > > > # return dict(form=form) > > > > > return dict(wrapper=wrapper, form=form) > > > > > > > # jQuery progress bar > > > > > progress = DIV(_id="progress") > > > > > def jqueryui_progress(): > > > > > wrapper = DIV(progress,_style="width:400px;") > > > > > page.include(" > http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/ > > > > > jquery-ui.min.js< > > >http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/%0Ajquery-ui.min.js > >", > > > > > download=True) > > > > > page.include(" > http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/ > > > > > themes/ui-darkness/jquery-ui.css< > > >http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/%0Athemes/ui-dark.. > > > .>", > > > > > download=True) > > > > > callback = js.call_function(get_progress) > > > > > page.ready(jq(progress).progressbar( dict(value='0') )() ) > > > > > page.ready(js.timer(callback,2000)) > > > > > return dict(wrapper=wrapper) > > > > > > > def get_progress(): > > > > > return jq(progress).progressbar('option', 'value', > > > > > request.now.second)()# > > > > > ________________________________________________________________ > > > > > > > But now i stuck.... can anyone put me on the right way? > > > > > When the Page is loaded, both elemts show up correctly. > > > > > When i do the submit: > > > > > - The Progressbar freezes(Callback dont work while downloading the > > > > > file...) > > > > > - The Download works and shows 100% when completed(but the while 1 > > > > > loop, which calls the report_hook dont work at all! and i need it > to > > > > > update the Progress bar... I think?) > > > > > > > + I need to change the Progressbar callback source when updating DB > > > > > after downloading the file... > > > > > > > Anyone any suggestions? > > > > > > > Best regards, > > > > > > > Dieter Asman > > > > > > > - AsmanCom - > > > > > Germany > > > > > > > -- > > > > > You received this message because you are subscribed to the Google > > > Groups > > > > > "web2py-users" group. > > > > > To post to this group, send email to [email protected]. > > > > > To unsubscribe from this group, send email to > > > > > [email protected]<web2py%[email protected]> > <web2py%[email protected]<web2py%[email protected]> > > > > > <web2py%[email protected]<web2py%[email protected]> > <web2py%[email protected]<web2py%[email protected]> > > > > > > > > > . > > > > > For more options, visit this group at > > > > >http://groups.google.com/group/web2py?hl=en. > > > > > -- > > > You received this message because you are subscribed to the Google > Groups > > > "web2py-users" group. > > > To post to this group, send email to [email protected]. > > > To unsubscribe from this group, send email to > > > [email protected]<web2py%[email protected]> > <web2py%[email protected]<web2py%[email protected]> > > > > > . > > > For more options, visit this group at > > >http://groups.google.com/group/web2py?hl=en. > > -- > You received this message because you are subscribed to the Google Groups > "web2py-users" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<web2py%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/web2py?hl=en. > > -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.
