Or python web2py.py -i 0.0.0.0 -p 8001 -a "password"
for all public IPs On Mar 8, 9:39 am, Kuba Kucharski <[email protected]> wrote: > yes, there is a mistake in my recipe > > should be: > > python web2py.py -i 127.0.0.1 -p 8001 -a "password" > > not: > > python web2py.py -i public_ip -p 8001 -a "password" > > here is a slice: > > http://www.web2pyslices.com/main/slices/take_slice/71 > > -- > Kuba -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.
