so I do (on the xmlrpc client)
import xmlrpclib
server=xmlrpclib.ServerProxy('http://77.72.228.30/vae/default/call/xmlrpc')
but I would like a timeout because oncoming line:
server.query(..
tends to hang the program when the server is down
I don't want threads. I just want it to timeout..
How to achieve this with PYTHON? as I understand this is proper xmlrpc
behaviour and I need a way around, and this is pretty hard to google..
--
Kuba
--
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/web2py?hl=en.