you can try define something like ths
def catch303(f):
try: return f()
except HTTP, http:
if http.status==303: return 'error'
raise http
and appy the additional decorator on top of auth.requires_login
@catch303
@auth.requires_login()
Massimo
On Apr 5, 10:50 pm, Alexei Vinidiktov <[email protected]>
wrote:
> I just tried it with this json-rpc lib
> (http://www.desfrenes.com/python-json-rpc) , and it also seems to work
> fine.
>
> I have many more open questions about authentication and
> authorization. I'm exploring different approaches for my application:
> cookie-based, basic, token authentication, and different protocols
> also (xmlrpc, jsonrpc, json).
>
> Another question: If the authentication fails, my client application
> receives "error 303 See Other".
>
> It is my understanding that this error means that the user visiting
> the website is redirected to a different page (apparently the page
> defined in auth.settings.login_url).
>
> Can I customize the error message such that the client application can
> understand that the error results from the failed login attempt?
>
>
>
> On Tue, Apr 6, 2010 at 10:55 AM, mdipierro <[email protected]> wrote:
> > thank you for trying it. It is one of those features that not many
> > people are using but should be solid.
>
> > Massimo
>
> > On Apr 5, 9:44 pm, Alexei Vinidiktov <[email protected]>
> > wrote:
> >> Thanks a lot, Massimo! It worked!
>
> >> On Tue, Apr 6, 2010 at 10:36 AM, mdipierro <[email protected]> wrote:
> >> > you need in db.py
>
> >> > auth.settings.allow_basic_login = True
>
> >> > it defaults to False
>
> >> > On Apr 5, 9:21 pm, Alexei Vinidiktov <[email protected]>
> >> > wrote:
> >> >> Hello,
>
> >> >> I'm trying to make a desktop client written in Python 2.5 (on Windows)
> >> >> communicate with a web2py 1.76.5 based app using services. It works
> >> >> fine with services that don't require authentication, but I was
> >> >> wondering if I could make it authenticate the user with Basic
> >> >> authentication.
>
> >> >> I've read in the Python docs that xmlrpclib supports Basic
> >> >> authentication:
>
> >> >> "
> >> >> Both the HTTP and HTTPS transports support the URL syntax extension
> >> >> for HTTP Basic Authentication:http://user:p...@host:port/path. The
> >> >> user:pass portion will be base64-encoded as an HTTP `Authorization'
> >> >> header, and sent to the remote server as part of the connection
> >> >> process when invoking an XML-RPC method.
> >> >> "
>
> >> >> In my modified Welcome web2py app I've added the setting
> >> >> auth.settings.allow_basic_authentication = True in
> >> >> welcome/models/db.py
>
> >> >> I've decorated the private_call action like so:
>
> >> >> @auth.requires_login()
> >> >> def private_call():
> >> >> return private_service()
>
> >> >> And I've added a test action getstring:
>
> >> >> @private_service.xmlrpc
> >> >> def getstring():
> >> >> if auth.is_logged_in():
> >> >> return "logged in!"
> >> >> else:
> >> >> return "not logged in!"
>
> >> >> In my desktop app I'm calling the service like this:
>
> >> >> self.server =
> >> >> xmlrpclib.Server("http://[email protected]:[email protected]:8000/welcome/default/private_call/xmlrpc";)
> >> >> print self.server.getstring()
>
> >> >> and I'm getting this traceback:
>
> >> >> Traceback (most recent call last):
> >> >> File "C:\Users\Alexei\Documents\wxPython\Boa\xml_rpc_test\Frame1.py",
> >> >> line 137
> >> >> , in OnButton4Button
> >> >> print self.server3.getstring()
> >> >> File "C:\Python25\lib\xmlrpclib.py", line 1147, in __call__
> >> >> return self.__send(self.__name, args)
> >> >> File "C:\Python25\lib\xmlrpclib.py", line 1437, in __request
> >> >> verbose=self.__verbose
> >> >> File "C:\Users\Alexei\Documents\wxPython\Boa\xml_rpc_test\Frame1.py",
> >> >> line 185
> >> >> , in request
> >> >> headers
> >> >> xmlrpclib.ProtocolError: <ProtocolError for
> >> >> [email protected]:mypassword@
> >> >> 127.0.0.1:8000/welcome/default/private_call/xmlrpc: 303 SEE OTHER>
>
> >> >> I'm obviously doing something wrong. Could you point me in the right
> >> >> direction?
>
> >> >> Thanks.
>
> >> >> --
> >> >> Alexei Vinidiktov
>
> >> > --
> >> > You received this message because you are subscribed to the Google
> >> > Groups "web2py-users" group.
> >> > To post to this group, send email to [email protected].
> >> > To unsubscribe from this group, send email to
> >> > [email protected].
> >> > For more options, visit this group
> >> > athttp://groups.google.com/group/web2py?hl=en.
>
> >> --
> >> Alexei Vinidiktov
>
> > --
> > You received this message because you are subscribed to the Google Groups
> > "web2py-users" group.
> > To post to this group, send email to [email protected].
> > To unsubscribe from this group, send email to
> > [email protected].
> > For more options, visit this group
> > athttp://groups.google.com/group/web2py?hl=en.
>
> --
> Alexei Vinidiktov
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