You can. Did you try
{{=form.custom.begin}}
<input ....>
{{=form.custom.end}}
On Apr 22, 11:35 pm, Paul Wray <[email protected]> wrote:
> I too have tried this without success.
>
> I seems that you cannot use a custom form together with SQLFORM with
> record=
> Is that true?
>
> Paul
>
> On Apr 9, 6:14 am, JmiXIII <[email protected]> wrote:
>
> > Hello,
>
> > I'm using a SQLFORM with a html custom (as described in book/7.2 =>
> > SQLFORM in HTML)
> > My fonction inside my controller is :
>
> > def ncmodif():
> > ### Formulaire de saisie des NC de production
> > rec=db(db.NC.id==269).select()[0]
> > form=SQLFORM(db.NC,record=rec)
> > if form.accepts(request.vars,formname='test'):
> > response.flash = 'form accepted'
> > elif form.errors:
> > response.flash = 'form has errors'
> > else:
> > response.flash = 'please fill the form'
> > return dict()
>
> > I have hardcoded db.NC.if==269 for the moment to see how it works.
>
> > My view is something like:
> > <form><input name="FieldName"/>....<input type="hidden"
> > name="_formname" value="test" />....
>
> > My question is there a simple way to make this form work as it works
> > with the standard way (ie when using {{=form}}) to update the record
> > via the custom form ?
> > Can I have the input field prepopulated and updated when I submit
> > since ncmodif() does not return any value ?
>
> > Thanks
>
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