Thanks.
The problem is that you are using the the user() action and that
returns form=auth() and that expects a certain convention for args(0).
Do not use user(). Make your own action
def combinedLogin(): return dict()
and in default/conbinedLogin.html you put
{{=auth.login()}}
{{=auth.register()}}
Massimo
On Apr 23, 3:11 am, scausten <[email protected]> wrote:
> Hi Massimo
>
> Firstly - amazing work on web2py - undoubtedly the best web framework
> I've come across :)
>
> I'm using essentially the same syntax you've written (I didn't put the
> braces in my example) and it works fine. What I want to do is expose a
> new url like /user/login or /user/register called /user/combinedLogin.
> I've tried this in default/user.html:
>
> {{if request.args(0)=="combinedLogin":}}
> {{=auth.login()}}
> {{=auth.register()}}
>
> but of course, when I browse to myapp/default/user/combinedLogin, I
> get a 404.
>
> How can I achieve this?
>
> On Apr 22, 9:53 pm, mdipierro <[email protected]> wrote:
>
> > How about
>
> > {{extend 'layout.html'}}
> > <h2>Login</h2>
> > {{=auth.login()}}
> > <h2>Register</h2>
> > {{=auth.register()}}
>
> > On Apr 22, 3:49 pm, scausten <[email protected]> wrote:
>
> > > Hi,
>
> > > Bit of a noob question (sorry) but I'd like to add a page "/user/
> > > combinedLogin" to my app, which combines the login and register forms,
> > > but can't work it out. This:
>
> > > if request.args(0)=="login":
> > > =auth.login()
> > > =auth.register()
>
> > > works fine, but I'd like to expose a new url (/user/combinedLogin).
>
> > > Any ideas?
>
> > > Si
>
> > > --
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