def index():
form=FORM((INPUT(_type='file',_name='myfile'),INPUT(_type='submit'))
if form.accepts(request.vars,session):
open(os.path.join(request.folder,'static','filename.txt'),'wb').write(form.myfile.file.read())
response.flash='uploaded'
return dict(form=form)
but you need to come up with a safe way to generate a 'filename.txt'
On 2 Lug, 18:40, Phyo Arkar <[email protected]> wrote:
> Anyway to Upload directly to Static Folder (none SQLForm, none DB)
> And Serve file without streaming and going through Controller?
