Following either
link = 'http://' + str(request.env.http_host) + URL('show',
args=row.id)
or
link = "http://127.0.0.1:8000"; + URL('show', args=row.id)
I get the link in the rss feed to the wiki page as
http://127.0.0.1:8000/mywiki/default/show.rss/1
On Sep 26, 7:11 pm, "Martin.Mulone" <[email protected]> wrote:
> better way:
>
> link = 'http://' + str(request.env.http_host) + URL('show',
> args=row.id)
>
> On 26 sep, 06:30, Tom Atkins <[email protected]> wrote:
>
>
>
>
>
>
>
> > Thanks for the replies. I worked out what the problem is. The code in the
> > book is incorrect. The line:
>
> > link = URL('show', args=row.id)
>
> > does not produce a full URL. The RSS service does not like this and fails.
>
> > If I replace it with:
>
> > link = "http://127.0.0.1:8000"; + URL('show', args=row.id)
>
> > then it all works fine. I'm sure there is a more elegant way to fix this!
>
> > Please update the example code in the book.
>
> > Thanks!
>
> > On 25 September 2010 19:08, mdipierro <[email protected]> wrote:
>
> > > it depends on the model. You must have wiki fields and your action
> > > must return record in the format described by the book in chapter 3.
>
> > > Massimo
>
> > > On Sep 25, 12:34 pm, Tom Atkins <[email protected]> wrote:
> > > > I've just copied and pasted from the online book the wiki application in
> > > > chapter 3. It all works great.
>
> > > > I've added the function for the rss feed to controller/default.py and if
> > > I
> > > > go to:
>
> > > >http://127.0.0.1:8000/mywiki/default/news
>
> > > > I get a nice page showing the wiki entries.
>
> > > > However if I go to:
>
> > > >http://127.0.0.1:8000/mywiki/default/news.rss
>
> > > > I just get a message saying 'no rss'...
>
> > > > Am I doing something stupid or is the code in the book wrong /
> > > incomplete.
>
> > > > Thanks for any help.
