I am trying many ways, does not works here
Calling directly in browser :
http://127.0.0.1:8000/examples/static/css/menu.css?version=1234 (Thats
works)
But when in layout.html:
{{response.files.append(URL(request.application,'static','css/menu.css',vars={'version':'1234'}))}}
or
{{response.files.append(URL(request.application,'static','css/menu.css',vars=dict(version='1234')))}}
Does not find the css file, Am I doing something wrong?
it is not important now, because I can solve putting CSS calling direct in
CSS, but other users may need the same.
2010/10/6 mdipierro <[email protected]>
> Is this better?
>
> {{response.files.append(URL(request.application,'static','css/
> home.css',vars=dict(version=random.random())))}}
>
> On Oct 5, 5:48 pm, Bruno Rocha <[email protected]> wrote:
> > Hi,
> >
> > Sometimes is useful to pass a random argument to a CSS file, matters of
> > cache, when you change something in your style and wants the user to have
> > the site updated without the need to clean the cache
> >
> > What I need is that CSS file will called as
> .../blablabla.css?version=12345
> > (ther argument does not matter, but browser will not use cached version)
> >
> > I tried in layout.html:
> >
> > <code>
> >
> {{response.files.append(URL(request.application,'static/css','home.css?version=12345'))}}
> >
> {{response.files.append(URL(request.application,'static/css','home.css',args='12345'))}}
> > </code>
> >
> > and
> >
> > <code>
> > import random
> >
> {{response.files.append(URL(request.application,'static/css','home.css',args=[random.random()]))}}
> >
> {{response.files.append(URL(request.application,'static/css','home.css',args=str(random.random())))}}
> > </code>
> >
> > But web2py does not loads CSS in this way.
>
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