Woah... I thought you had to do... URL(r=request, c='defaut', f='index',args=[1,2,3]) I am such an old school web2py'r :) Jason On Wed, 2010-10-20 at 15:22 -0700, Eric Vicenti wrote:
> Vlad,
>
> URL is quite versatile. Not only can you do URL('function') for a
> function in the current controller, you can use
> URL('controller','function') or even
> URL('application','controller','function') if you need.
>
> I hope I was able to help.
>
> -Eric
>
> On Oct 20, 11:37 am, Alucard <[email protected]> wrote:
> > Hey there, I'm a long time Django programmer getting to know web2py
> > and I've loved it so far.
> >
> > I have a simple question: how do I access another function inside
> > another controller?
> >
> > lets say that Im building an URL like this
> >
> > {{=LI(A(image.title, _href=URL("show", args=image.id)))}}
> >
> > that is assuming that "show" is another function in the same
> > controller, in this case, default.py and by having that, it will
> > automatically build the URL but, how do I build it if I have another
> > function in another controller? something like a file called
> > controller2.py with a function called myfunc.py??
> >
> > Thanks!
> > Vlad
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