submit = conversion_form.element('input',_type='submit')
submit['_style'] = 'display:none;'
or with CSS
form#conversion_dropdown input[type=submit] {
display:none;
}
On Oct 24, 11:36 am, Luther Goh Lu Feng <[email protected]> wrote:
> conversation_dropdown = SQLFORM.factory(
> Field('text', label='Select a conversation',
> requires=IS_IN_DB(db,
> 'question.id','question.text')),
> _id='conversation_dropdown')
>
> On Oct 24, 11:47 pm, "mr.freeze" <[email protected]> wrote:
>
> > How are you creating the form? Can you show the code?
>
> > On Oct 24, 10:45 am, Luther Goh Lu Feng <[email protected]> wrote:
>
> > > I see. How do I filter the specific form that has id='myform'?
>
> > > On Oct 24, 11:30 pm, "mr.freeze" <[email protected]> wrote:
>
> > > > This is how I do it. There may be a better way.
>
> > > > def myform():
> > > > form = SQLFORM.factory(Field('test'))
> > > > submit = form.element('input',_type='submit')
> > > > submit['_style'] = 'display:none;'
> > > > return dict(form=form)
>
> > > > You could always just use a CSS rule too
>
> > > > On Oct 24, 10:21 am, Luther Goh Lu Feng <[email protected]> wrote:
>
> > > > > I have created a dropdown list, using SQLFORM.factory which will
> > > > > autosubmitted
> > > > > using ajax when there is a change in selection.
>
> > > > > However the form generated has a submit button, which I would like to
> > > > > hide. I
> > > > > would like to ask for tips regarding this.
>
>
