i got xmlrpclib to transfer a file from python script to web2py app
Here is my code
*Python script*
import xmlrpclib
server = xmlrpclib.ServerProxy('
http://127.0.0.1:8000/CrossValidation1/default/call/xmlrpc')
filepath='c:\\'
filename='ico.gif'
filebin = xmlrpclib.Binary(open(filepath+filename).read())
server.checkflow(filebin,filename)
*
and in my default.py controller*
import xmlrpclib
import os
@service.xmlrpc
def checkflow(file,name):
basedir= request.folder.replace('/','')
f=open(basedir+'\\uploads\\'+name,'wb')
db.image.insert(file=name)
f.write(file.data)
f.close()
print "ok"
return name
def call():
session.forget()
return service()
*
my model*
*
*db.define_table('image',
Field('file','upload'))
Is this a good practice?
2010/11/24 mdipierro <mdipie...@cs.depaul.edu>
> No
>
>
> filename = request.vars.varwithFile.filename or 'filename.txt'
> stream = request.vars.varwithFile.file or open(filename,'rb')
> db.photo.insert(file=db.photo.file.store(stream),filename=filename)
>
>
> On Nov 24, 3:37 pm, António Ramos <ramstei...@gmail.com> wrote:
> > but if i want, using the shell, to add and image manually
> > do i use
> > db.photo.insert('file'=varwithFile)
> > ?????
> >
> > *my test model is
> > db.define_table('photo',
> > Field('file','upload'))*
> >
> > Best regards
> > António
>
