The reason I use folder='uploads' in the get_path arg list is because I use this same routine to get files that have been stored in various places: uploads, static, static/data ... etc.
On Dec 12, 8:41 pm, "G. Clifford Williams" <[email protected]> wrote: > Awesome thanks. > > On Sun, Dec 12, 2010 at 10:25:25AM -0800, weheh spake: > > > If uploadseparate=True then you have to reconstruct the full path with > > a routine like this: > > > def get_path(filename,folder='uploads'): > > """Get full path to file stored in uploads""" > > f=filename.split('.') > > path=os.path.join(request.folder,folder, > > '%s.%s'%(f[0],f[1]), > > '%c%c'%(f[2][0],f[2][1]), > > filename) > > return path > > > where filename passed to get_path is db.mytable[row].file_fieldname > > > On Dec 12, 1:07 pm, "G. Clifford Williams" <[email protected]> > > wrote: > > > Is ther a prescribed mechanism for getting the full path to uploaded > > > files? > > > > I've got an onaccept function that contains: > > > os.symlink(os.path.join(request.folder,'uploads', > > > form.vars.file_newfilename), link_path) > > > > which worked until I'd changed the field to use 'uploadseparate=True' > > > > Thanks in advance > > > --Cliff > >
