For me works following syntax too:
IS_IN_SET((("yes",T("yes")), ("no",T("no"))))
IS_IN_SET(((1,T("yes")), (0,T("no"))))On 27 led, 21:33, DenesL <[email protected]> wrote: > You can use > requires=IS_IN_SET({1:'Fixed yesterday', 2:'to be fixed today', ...})
