There is a shortcut for this:
def add():
return dict(form=crud.create(db.accmgr,next='view/[id]'))
On Feb 6, 9:55 am, Running Clam <[email protected]> wrote:
> Hi All,
>
> Using CRUD methods, in a controller I have: -
>
> def update():
> crud.settings.showid = True
> crud.settings.update_next = URL('view',
> args=[request.args(0),request.args(1)])
> return dict(form=crud.update(db.accmgr,
> request.args(1)))
>
> ...and update_next takes me to view the record updated, using the id in
> the request to identify the record.
>
> If I try to do the equivalent with an insert, I need to access the ID of
> the inserted record, which I had understood to be accessible via
> "form.vars.id" but if I try: -
>
> def add():
> crud.settings.create_next = URL('view', args=['accmgr',
> form.vars.id])
> return dict(form=crud.create(db.accmgr))
>
> ...I get an error ticket telling me that "form is not defined".
>
> I have read that "form.vars.id" works with "onaccept", because
> "onaccept" is called with "form" as a parameter after the form is
> accepted, but that does not seem to apply here.
>
> Do I need to somehow explicitly make the "create_next" conditional on
> the form having been accepted, or is there a different syntax I can use
> to access the "id", or am I on the wrong track entirely?
>
> --
>
> Cheers,
>
> Clam
