Hi Massimo,
When "uploadseparate" is set to True, previously mentioned solution
will not work, at least not for me.
Although, Bruno gave us one suggestion, I would prefer to use explicit
image location rather than image ID.
To explain:
###model:
db.define_table("image",
...
Field('file',"upload",uploadseparate=True,required=True,uploadfolder=request.folder
+'static/' ),
...
###view
{{url = URL('static',image.file)}}
{{=A(IMG(_src=url), _href=url)}}
This would give invalid file location:
"
<a href="app/static/image.file.9197cf1918d6a0fa.
6b617374656c61352e6a7067.jpg"><img src="app/static/image.file.
9197cf1918d6a0fa.6b617374656c61352e6a7067.jpg" /></a>
"
while correct url is
127.0.0.1/app/static/image.file/91/image.file.
9197cf1918d6a0fa.6b617374656c61352e6a7067.jpg
In attempt to find a solution, I was playing with SUBSTR, but I'm not
getting clean output (I'm not sure if this is good approach, specially
from portability point of view)
###contr
...
img_folder= db............select(db.image.file [11:13])
return dict(img_folder=img_folder)
###view
{{=img_folder}}
and output is
"
SUBSTR(image.file,12,(14 - 12))
91
"
If you could give me some pointers, that would be greatly appreciated.
Thanks
IK
On Jun 17, 3:18 pm, Massimo Di Pierro <[email protected]>
wrote:
> This is fine:
>
> db.define_table('announce',
> Field('picture','upload',uploadfolder=request.folder+'static/
> pictures'),
> )
>
> but why do you need an action to download from the static folder? Why
> not simply use
>
> URL('static',record.picture)
>
> On Jun 17, 5:56 am, Bruno Rocha <[email protected]> wrote:
>
>
>
>
>
>
>
> > For security reasons, web2py does not expose the 'uploads' folder to the
> > user, this folder can be accessed only by the 'download' function.
>
> > The best way is to set the upload path pointing to /static not to /upload
> > and you will have youruploadedfiles to be served as static files,
> > bypassing download function.
>
> > under /static create a folder called 'picture'
>
> > *Go to the table definition and do this:*
>
> > *<model>*
> > db.define_table('announce',
>
> > Field('picture','upload',uploadfolder=request.folder+'static/pictures'),
> > )
> > *</model>*
>
> > You are saying DAL to store uploades files in to that folder under static
> > and store the ath in the field.
>
> > Now in your controller create a function do handle that (different from
> > download, it is a kind of viewer)
>
> > *<controller>*
> > def viewer():
> > row = db(db.announce.id
> > ==request.args(0)).select(db.announce.picture).first()
> > redirect(URL('static','pictures',args=row.picture))
> > *</controller>*
>
> > *Now you can fo this:*
>
> >http://server/app/default/viewer/3#record id
>
> > then you got redirected to theimage(no html page)
>
> > example:http://127.0.0.1:8000/app/static/pictures/announce.picture.aaf5d3f777...
>
> > you can always referdirectlyto theimagepath (not using the viewer
> > function) but you always need to fetch the picture name from db.
>
> > Hope it helps.
>
> > Should go on the book?
>
> > --
> > Bruno Rocha
> > [ About me:http://zerp.ly/rochacbruno]
> > [ Aprenda a programar:http://CursoDePython.com.br]
>
> > On Thu, Jun 16, 2011 at 6:09 AM, Vinicius Assef
> > <[email protected]>wrote:
>
> > > Hi guys.
>
> > > I have a table (called anuncio) with an upload field (called foto), so
> > > anuncio.foto is my upload field.
>
> > > I'm showing andlinkingit with this piece of code in my view :
> > > {{url = URL(c='anuncios',f='download', args=['uploads',
> > > anuncio.foto])}}
> > > {{=A(IMG(_src=url), _href=url)}}
>
> > > My /contollers/anuncios.py/download() function is the default, as seen
> > > below:
> > > def download():
> > > return response.download(request,db)
>
> > > When user clicks on thisimage, browser shows the download dialog,
> > > asking him/her where to save theimage.
> > > But I'd like to simply show theimage, not present the download
> > > dialog. All these images will be public.
>
> > > How I solved it:
> > > 1) I entered in /myapp/static/images and created a symbolic link
> > > called 'uploads' pointing to /myapp/uploads.
> > > 2) In my view, I changed the: {{url = URL(...}} stuff by this: {{url =
> > > URL(c='static', f='images', args=['uploads', anuncio.foto])}}
>
> > > I think this isn't the best choice because I'm pointing URL() to a
> > > fake controller and function, and I'm counting on an external
> > > resource: a symbolic link in my filesystem.
>
> > > How would be the "web2pythonic" way to do this?
>
> > > --
> > > Vinicius Assef.
