done. thanks

On Aug 18, 5:56 pm, dkuhlman <[email protected]> wrote:
> On Aug 18, 12:55 pm, Carlos <[email protected]> wrote:
>
>
>
>
>
>
>
>
>
> > Hi,
>
> > I get the following:
>
> > C:\web2py>python web2py.py -S myapp -M -N
> > web2py Web Framework
> > Created by Massimo Di Pierro, Copyright 2007-2011
> > Version 1.98.2 (2011-08-18 05:41:57)
> > Database drivers available: SQLite3, pymysql, PostgreSQL
> > *WARNING:web2py:import IPython error; use default python shell*
> > Python 2.6.4 (r264:75708, Oct 26 2009, 08:23:19) [MSC v.1500 32 bit (Intel)]
> > on win32
> > Type "help", "copyright", "credits" or "license" for more information.
> > (InteractiveConsole)
>
> So, if we want it to work for both new and older versions of IPython,
> we could use the following:
>
> #
> =========================================================================== 
> =======
>                 try:
>                     import IPython
>                     if IPython.__version__ >= '0.11':
>                         from IPython.frontend.terminal.embed import
> InteractiveShellEmbed
>                         shell = InteractiveShellEmbed(user_ns=_env)
>                         shell()
>                         return
>                     else:
>                         # following 2 lines fix a problem with
> IPython; thanks Michael Toomim
>                         if '__builtins__' in _env:
>                             del _env['__builtins__']
>                         shell = IPython.Shell.IPShell(argv=[],
> user_ns=_env)
>                         shell.mainloop()
>                         return
>                 except:
>                     logger.warning(
>                         'import IPython error; use default python
> shell')
> #
> =========================================================================== 
> =======
>
> I'm a little uncomfortable doing a compare greater than or equal on
> a string, but it seems to work.
>
> An alternative is to require IPython version 0.11 or later, but
> I suppose that is a bit severe.
>
> - Dave

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