is your file stored as a BLOB or a regular file under /uploads folder? 2011/9/15 António Ramos <[email protected]>
> hello, > i receive a file via xmlrpc > this is my function > > @service.xmlrpc > def checkflow(file,name): > > db.image.insert(file=db.image.file.store(cStringIO.StringIO(file.data),name)) > return "ok" > > It is working as expected. > > Now i want to open the file and process every line > > how do i code the opening of the file ? > > > thank you > -- -- Bruno Rocha [ About me: http://zerp.ly/rochacbruno ] [ Aprenda a programar: http://CursoDePython.com.br ] [ O seu aliado nos cuidados com os animais: http://AnimalSystem.com.br ] [ Consultoria em desenvolvimento web: http://www.blouweb.com ]
