I did look at that Bruno, but some of the articles I read suggested that it is not very memory efficient?
Chris On Sep 19, 2011 3:44 PM, "Bruno Rocha" <[email protected]> wrote: > I use xml minidom and it is easier. > > http://zerp.ly/rochacbruno > Em 19/09/2011 11:40, "Chris Rowson" <[email protected]> escreveu: >> Thank you Michele, >> >> Chris >> >> On Mon, Sep 19, 2011 at 2:00 PM, Michele Comitini >> <[email protected]> wrote: >>> There is nothing wrong with your code. Maybe it is better to use >>> find() to get the <geo> tag. >>> If you have an XSD schema you can use generateDS >>> http://www.rexx.com/~dkuhlman/generateDS.html >>> to have a python parser. >>> >>> But if you can use the JSON API... much simpler. >>> >>> mic >>> >>> >>> 2011/9/19 Chris Rowson <[email protected]>: >>>> Anybody using xml.etree? >>>> >>>> I asked this question over at the Python tutors group but it seems >>>> that few people there had experience of it. >>>> >>>> I'm trying to access a UK postcode API at www.uk-postcodes.com to take >>>> a UK postcode and return the lat/lng of the postcode. This is what the >>>> XML looks like: http://www.uk-postcodes.com/postcode/HU11AA.xml >>>> >>>> The function below returns a dict with the xml tag as a key and the >>>> text as a value. Is this a correct way to use xml.etree? Is there a >>>> better way of doing this? >>>> >>>> Thanks in advance! >>>> >>>> Chris >>>> >>>> >>>> def ukpostcodesapi(postcode): >>>> import urllib >>>> import xml.etree.ElementTree as etree >>>> >>>> baseURL='http://www.uk-postcodes.com/' >>>> geocodeRequest='postcode/'+postcode+'.xml' >>>> >>>> #grab the xml >>>> tree=etree.parse(urllib.urlopen(baseURL+geocodeRequest)) >>>> root=tree.getroot() >>>> results={} >>>> for child in root[1]: #here's the geo tag >>>> results.update({child.tag:child.text}) #build a dict >>>> containing the geocode data >>>> return results >>>> >>>> #example usage (testing the function) >>>> results = ukpostcodesapi('hu11aa') >>>> print results['lat']+' '+results['lng'] >>>> >>>
