I think you need to use the radio widget in conjunction with the IS_IN_SET
or IS_IN_DB validator (it creates the radio button options from the
labels/values specified in those validators).
Anthony
On Tuesday, October 11, 2011 10:45:38 AM UTC-4, Web2Py Freak wrote:
>
> am trying to use SQLFORM.factory with a widget but its not working :
>
> def booking():
> content=db(db.page.title=='booking').select(db.page.ALL)
> form = SQLFORM.factory(
> Field('your_name', requires=IS_NOT_EMPTY()),
> Field('your_email'),
> Field('like',widget=SQLFORM.widgets.radio.widget)
> )
> if form.accepts(request.vars,session):
> response.flash = 'form accepted'
>
> elif form.errors:
> response.flash = 'form has errors'
> return dict(content=content,form=form)
>
>
>
> the error is :
>
> <type 'exceptions.SyntaxError'>(widget cannot determine options of
> no_table.like)
>
>
> what to do ??!
